x-4/5x^2-7

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Solution for x-4/5x^2-7 equation: 


x in (-oo:+oo)

x-((4/5)*x^2)-7 = 0

(-4/5)*x^2+x-7 = 0

x-4/5*x^2-7 = 0

DELTA = 1^2-(-7*(-4/5)*4)

DELTA = -107/5

DELTA < 0

x belongs to the empty set

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